Base | Representation |
---|---|
bin | 10011001000010001001… |
… | …110100101101010011101 |
3 | 11122200002011220201201211 |
4 | 103020101032211222131 |
5 | 133014144022421113 |
6 | 2443521231504421 |
7 | 163654515250165 |
oct | 23102116455235 |
9 | 4580064821654 |
10 | 1314549029533 |
11 | 467551725443 |
12 | 192927988111 |
13 | 96c66396b5c |
14 | 478a593b5a5 |
15 | 242db358b3d |
hex | 132113a5a9d |
1314549029533 has 8 divisors (see below), whose sum is σ = 1321930648800. Its totient is φ = 1307167830288.
The previous prime is 1314549029503. The next prime is 1314549029537. The reversal of 1314549029533 is 3359209454131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1314549029533 - 213 = 1314549021341 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1314549029537) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7862910 + ... + 8028352.
It is an arithmetic number, because the mean of its divisors is an integer number (165241331100).
Almost surely, 21314549029533 is an apocalyptic number.
It is an amenable number.
1314549029533 is a deficient number, since it is larger than the sum of its proper divisors (7381619267).
1314549029533 is a wasteful number, since it uses less digits than its factorization.
1314549029533 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 210011.
The product of its (nonzero) digits is 1749600, while the sum is 49.
The spelling of 1314549029533 in words is "one trillion, three hundred fourteen billion, five hundred forty-nine million, twenty-nine thousand, five hundred thirty-three".
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