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13145659593007 = 52999248035993
BaseRepresentation
bin1011111101001011011001…
…0111101101000100101111
31201112201020121201112002111
42333102312113231010233
53210334302323434012
643543011015104451
72524512461615014
oct277226627550457
951481217645074
1013145659593007
114209052151927
121583872972127
13744826c3b4c6
1433637917170b
1517be3719eba7
hexbf4b65ed12f

13145659593007 has 4 divisors (see below), whose sum is σ = 13145907682000. Its totient is φ = 13145411504016.

The previous prime is 13145659592963. The next prime is 13145659593043. The reversal of 13145659593007 is 70039595654131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13145659593007 - 239 = 12595903779119 is a prime.

It is a super-2 number, since 2×131456595930072 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13145659593707) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 123964998 + ... + 124070995.

It is an arithmetic number, because the mean of its divisors is an integer number (3286476920500).

Almost surely, 213145659593007 is an apocalyptic number.

13145659593007 is a deficient number, since it is larger than the sum of its proper divisors (248088993).

13145659593007 is an equidigital number, since it uses as much as digits as its factorization.

13145659593007 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 248088992.

The product of its (nonzero) digits is 15309000, while the sum is 58.

The spelling of 13145659593007 in words is "thirteen trillion, one hundred forty-five billion, six hundred fifty-nine million, five hundred ninety-three thousand, seven".

Divisors: 1 52999 248035993 13145659593007