Base | Representation |
---|---|
bin | 1011111101001011011001… |
… | …0111101101000100101111 |
3 | 1201112201020121201112002111 |
4 | 2333102312113231010233 |
5 | 3210334302323434012 |
6 | 43543011015104451 |
7 | 2524512461615014 |
oct | 277226627550457 |
9 | 51481217645074 |
10 | 13145659593007 |
11 | 4209052151927 |
12 | 1583872972127 |
13 | 744826c3b4c6 |
14 | 33637917170b |
15 | 17be3719eba7 |
hex | bf4b65ed12f |
13145659593007 has 4 divisors (see below), whose sum is σ = 13145907682000. Its totient is φ = 13145411504016.
The previous prime is 13145659592963. The next prime is 13145659593043. The reversal of 13145659593007 is 70039595654131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13145659593007 - 239 = 12595903779119 is a prime.
It is a super-2 number, since 2×131456595930072 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13145659593707) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 123964998 + ... + 124070995.
It is an arithmetic number, because the mean of its divisors is an integer number (3286476920500).
Almost surely, 213145659593007 is an apocalyptic number.
13145659593007 is a deficient number, since it is larger than the sum of its proper divisors (248088993).
13145659593007 is an equidigital number, since it uses as much as digits as its factorization.
13145659593007 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 248088992.
The product of its (nonzero) digits is 15309000, while the sum is 58.
The spelling of 13145659593007 in words is "thirteen trillion, one hundred forty-five billion, six hundred fifty-nine million, five hundred ninety-three thousand, seven".
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