Base | Representation |
---|---|
bin | 11101111001000100010111… |
… | …000010110000111110100011 |
3 | 122020110221020201022002002022 |
4 | 131321010113002300332203 |
5 | 114212410400341023011 |
6 | 1143334112245412055 |
7 | 36456015155061461 |
oct | 3571042702607643 |
9 | 566427221262068 |
10 | 131465040564131 |
11 | 38986013125a5a |
12 | 128b298010a02b |
13 | 584813bcab361 |
14 | 2466d2887b831 |
15 | 102ea927268db |
hex | 7791170b0fa3 |
131465040564131 has 8 divisors (see below), whose sum is σ = 139442058076464. Its totient is φ = 123515109699840.
The previous prime is 131465040564101. The next prime is 131465040564167.
It is a happy number.
131465040564131 is nontrivially palindromic in base 10.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131465040564131 - 210 = 131465040563107 is a prime.
It is a super-2 number, since 2×1314650405641312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131465040564101) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6771652010 + ... + 6771671423.
It is an arithmetic number, because the mean of its divisors is an integer number (17430257259558).
Almost surely, 2131465040564131 is an apocalyptic number.
131465040564131 is a deficient number, since it is larger than the sum of its proper divisors (7977017512333).
131465040564131 is a wasteful number, since it uses less digits than its factorization.
131465040564131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13543324021.
The product of its (nonzero) digits is 518400, while the sum is 44.
The spelling of 131465040564131 in words is "one hundred thirty-one trillion, four hundred sixty-five billion, forty million, five hundred sixty-four thousand, one hundred thirty-one".
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