Base | Representation |
---|---|
bin | 1011111101010101011100… |
… | …1010100010100111000011 |
3 | 1201112222012121212220210020 |
4 | 2333111113022202213003 |
5 | 3210410313430232201 |
6 | 43544134423504523 |
7 | 2524636356542226 |
oct | 277252712424703 |
9 | 51488177786706 |
10 | 13148357274051 |
11 | 420a2069a459a |
12 | 15842a62b8143 |
13 | 744b66ac258c |
14 | 33655355d5bd |
15 | 17c043e27a36 |
hex | bf5572a29c3 |
13148357274051 has 32 divisors (see below), whose sum is σ = 17762607862272. Its totient is φ = 8650442960640.
The previous prime is 13148357274049. The next prime is 13148357274079. The reversal of 13148357274051 is 15047275384131.
It is not a de Polignac number, because 13148357274051 - 21 = 13148357274049 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13148357273985 and 13148357274003.
It is not an unprimeable number, because it can be changed into a prime (13148357274251) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 414223041 + ... + 414254781.
It is an arithmetic number, because the mean of its divisors is an integer number (555081495696).
Almost surely, 213148357274051 is an apocalyptic number.
13148357274051 is a deficient number, since it is larger than the sum of its proper divisors (4614250588221).
13148357274051 is a wasteful number, since it uses less digits than its factorization.
13148357274051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 36443.
The product of its (nonzero) digits is 2822400, while the sum is 51.
The spelling of 13148357274051 in words is "thirteen trillion, one hundred forty-eight billion, three hundred fifty-seven million, two hundred seventy-four thousand, fifty-one".
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