Base | Representation |
---|---|
bin | 11000011111011010… |
… | …01101010000110111 |
3 | 1020221100001110222210 |
4 | 30033231031100313 |
5 | 203411443122220 |
6 | 10012412024503 |
7 | 643554435402 |
oct | 141755152067 |
9 | 36840043883 |
10 | 13148410935 |
11 | 5637a31820 |
12 | 266b462133 |
13 | 131706551a |
14 | 8ca35cd39 |
15 | 51e4ba6e0 |
hex | 30fb4d437 |
13148410935 has 16 divisors (see below), whose sum is σ = 22949953920. Its totient is φ = 6374987040.
The previous prime is 13148410901. The next prime is 13148410937. The reversal of 13148410935 is 53901484131.
It is not a de Polignac number, because 13148410935 - 28 = 13148410679 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13148410893 and 13148410902.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13148410937) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 39843505 + ... + 39843834.
It is an arithmetic number, because the mean of its divisors is an integer number (1434372120).
Almost surely, 213148410935 is an apocalyptic number.
13148410935 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13148410935 is a deficient number, since it is larger than the sum of its proper divisors (9801542985).
13148410935 is a wasteful number, since it uses less digits than its factorization.
13148410935 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 79687358.
The product of its (nonzero) digits is 51840, while the sum is 39.
The spelling of 13148410935 in words is "thirteen billion, one hundred forty-eight million, four hundred ten thousand, nine hundred thirty-five".
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