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131490811486903 = 1111953710135173
BaseRepresentation
bin11101111001011100010111…
…000111000010001010110111
3122020120101202201211121010111
4131321130113013002022313
5114213321140220040103
61143354013410003451
736460616613233221
oct3571342707021267
9566511681747114
10131490811486903
1138995a38142740
12128b7972876587
13584a6b815679b
142468291381411
15103059ee2a86d
hex7797171c22b7

131490811486903 has 4 divisors (see below), whose sum is σ = 143444521622088. Its totient is φ = 119537101351720.

The previous prime is 131490811486891. The next prime is 131490811486927. The reversal of 131490811486903 is 309684118094131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131490811486903 - 229 = 131490274615991 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131490811486003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5976855067576 + ... + 5976855067597.

It is an arithmetic number, because the mean of its divisors is an integer number (35861130405522).

Almost surely, 2131490811486903 is an apocalyptic number.

131490811486903 is a deficient number, since it is larger than the sum of its proper divisors (11953710135185).

131490811486903 is a wasteful number, since it uses less digits than its factorization.

131490811486903 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11953710135184.

The product of its (nonzero) digits is 4478976, while the sum is 58.

The spelling of 131490811486903 in words is "one hundred thirty-one trillion, four hundred ninety billion, eight hundred eleven million, four hundred eighty-six thousand, nine hundred three".

Divisors: 1 11 11953710135173 131490811486903