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13150053431 = 129710138823
BaseRepresentation
bin11000011111100110…
…11110010000110111
31020221110010221001222
430033303132100313
5203412403202211
610012511140555
7643604416124
oct141763362067
936843127058
1013150053431
115638953859
12266bb1475b
1313174bc008
148ca66974b
1551e6e21db
hex30fcde437

13150053431 has 4 divisors (see below), whose sum is σ = 13160193552. Its totient is φ = 13139913312.

The previous prime is 13150053421. The next prime is 13150053461. The reversal of 13150053431 is 13435005131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13150053431 - 218 = 13149791287 is a prime.

It is a super-2 number, since 2×131500534312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13150053431.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13150053421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5068115 + ... + 5070708.

It is an arithmetic number, because the mean of its divisors is an integer number (3290048388).

Almost surely, 213150053431 is an apocalyptic number.

13150053431 is a deficient number, since it is larger than the sum of its proper divisors (10140121).

13150053431 is a wasteful number, since it uses less digits than its factorization.

13150053431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10140120.

The product of its (nonzero) digits is 2700, while the sum is 26.

Adding to 13150053431 its reverse (13435005131), we get a palindrome (26585058562).

The spelling of 13150053431 in words is "thirteen billion, one hundred fifty million, fifty-three thousand, four hundred thirty-one".

Divisors: 1 1297 10138823 13150053431