Base | Representation |
---|---|
bin | 10011001000101100110… |
… | …010100101010010010011 |
3 | 11122201021102001010100220 |
4 | 103020230302211102103 |
5 | 133021120412400003 |
6 | 2444035151044123 |
7 | 164002131616626 |
oct | 23105462452223 |
9 | 4581242033326 |
10 | 1315011450003 |
11 | 467769754819 |
12 | 192a36810643 |
13 | 9700b122034 |
14 | 4790b10ddbd |
15 | 24316c4c353 |
hex | 1322cca5493 |
1315011450003 has 8 divisors (see below), whose sum is σ = 1775542886400. Its totient is φ = 865577156808.
The previous prime is 1315011450001. The next prime is 1315011450023. The reversal of 1315011450003 is 3000541105131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1315011450003 - 21 = 1315011450001 is a prime.
It is a super-2 number, since 2×13150114500032 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1315011450001) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2774285523 + ... + 2774285996.
It is an arithmetic number, because the mean of its divisors is an integer number (221942860800).
Almost surely, 21315011450003 is an apocalyptic number.
1315011450003 is a deficient number, since it is larger than the sum of its proper divisors (460531436397).
1315011450003 is an equidigital number, since it uses as much as digits as its factorization.
1315011450003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5548571601.
The product of its (nonzero) digits is 900, while the sum is 24.
Adding to 1315011450003 its reverse (3000541105131), we get a palindrome (4315552555134).
The spelling of 1315011450003 in words is "one trillion, three hundred fifteen billion, eleven million, four hundred fifty thousand, three".
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