Search a number
-
+
13151440033 = 69831883351
BaseRepresentation
bin11000011111110001…
…10000110010100001
31020221112202101010121
430033320300302201
5203413232040113
610013001000241
7643622252524
oct141770606241
936845671117
1013151440033
115639710606
122670483081
1313178861a4
148ca90abbb
1551e8b7e8d
hex30fe30ca1

13151440033 has 4 divisors (see below), whose sum is σ = 13153330368. Its totient is φ = 13149549700.

The previous prime is 13151440019. The next prime is 13151440051. The reversal of 13151440033 is 33004415131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13151440033 - 233 = 4561505441 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13151440013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 934693 + ... + 948658.

It is an arithmetic number, because the mean of its divisors is an integer number (3288332592).

Almost surely, 213151440033 is an apocalyptic number.

It is an amenable number.

13151440033 is a deficient number, since it is larger than the sum of its proper divisors (1890335).

13151440033 is an equidigital number, since it uses as much as digits as its factorization.

13151440033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1890334.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 13151440033 its reverse (33004415131), we get a palindrome (46155855164).

The spelling of 13151440033 in words is "thirteen billion, one hundred fifty-one million, four hundred forty thousand, thirty-three".

Divisors: 1 6983 1883351 13151440033