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1315232504345 = 51032553849523
BaseRepresentation
bin10011001000111001111…
…101110101101000011001
311122201211210222211220202
4103020321331311220121
5133022044010114340
62444113125031545
7164010454554134
oct23107175655031
94581753884822
101315232504345
11467872508161
12192a988555b5
1397044b6b616
144792c61321b
152432b364c15
hex13239f75a19

1315232504345 has 8 divisors (see below), whose sum is σ = 1593602102976. Its totient is φ = 1041970604976.

The previous prime is 1315232504297. The next prime is 1315232504371. The reversal of 1315232504345 is 5434052325131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1315232504345 - 26 = 1315232504281 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1315232504299 and 1315232504308.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1276924247 + ... + 1276925276.

It is an arithmetic number, because the mean of its divisors is an integer number (199200262872).

Almost surely, 21315232504345 is an apocalyptic number.

It is an amenable number.

1315232504345 is a deficient number, since it is larger than the sum of its proper divisors (278369598631).

1315232504345 is a wasteful number, since it uses less digits than its factorization.

1315232504345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2553849631.

The product of its (nonzero) digits is 216000, while the sum is 38.

Adding to 1315232504345 its reverse (5434052325131), we get a palindrome (6749284829476).

The spelling of 1315232504345 in words is "one trillion, three hundred fifteen billion, two hundred thirty-two million, five hundred four thousand, three hundred forty-five".

Divisors: 1 5 103 515 2553849523 12769247615 263046500869 1315232504345