Base | Representation |
---|---|
bin | 11101111001111100101000… |
… | …100101111000100101001011 |
3 | 122020200201012202122022222210 |
4 | 131321330220211320211023 |
5 | 114214403122404301011 |
6 | 1143421544140520203 |
7 | 36463254423215205 |
oct | 3571745045704513 |
9 | 566621182568883 |
10 | 131525464525131 |
11 | 389a96aa954206 |
12 | 12902623b50063 |
13 | 5850a4b519131 |
14 | 2469c1b771775 |
15 | 103142c2c26a6 |
hex | 779f2897894b |
131525464525131 has 32 divisors (see below), whose sum is σ = 183590089360128. Its totient is φ = 83679691766400.
The previous prime is 131525464525121. The next prime is 131525464525153.
131525464525131 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 131525464525131 - 210 = 131525464524107 is a prime.
It is a super-2 number, since 2×1315254645251312 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (131525464525121) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 53622025 + ... + 56021178.
It is an arithmetic number, because the mean of its divisors is an integer number (5737190292504).
Almost surely, 2131525464525131 is an apocalyptic number.
131525464525131 is a deficient number, since it is larger than the sum of its proper divisors (52064624834997).
131525464525131 is a wasteful number, since it uses less digits than its factorization.
131525464525131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 109643451.
The product of its digits is 2160000, while the sum is 48.
The spelling of 131525464525131 in words is "one hundred thirty-one trillion, five hundred twenty-five billion, four hundred sixty-four million, five hundred twenty-five thousand, one hundred thirty-one".
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