13153050301 has 4 divisors (see below), whose sum is σ = 13153281472. Its totient is φ = 13152819132.

The previous prime is 13153050293. The next prime is 13153050343. The reversal of 13153050301 is 10305035131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13153050301 - 2³ = 13153050293 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13153050101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36220 + ... + 166186.

It is an arithmetic number, because the mean of its divisors is an integer number (3288320368).

Almost surely, 2^13153050301 is an apocalyptic number.

It is an amenable number.

13153050301 is a deficient number, since it is larger than the sum of its proper divisors (231171).

13153050301 is a wasteful number, since it uses less digits than its factorization.

13153050301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 231170.

The product of its (nonzero) digits is 675, while the sum is 22.

Adding to 13153050301 its reverse (10305035131), we get a palindrome (23458085432).

The spelling of 13153050301 in words is "thirteen billion, one hundred fifty-three million, fifty thousand, three hundred one".