Base | Representation |
---|---|
bin | 11000100000000000… |
… | …10010001111000011 |
3 | 1020221200110120012201 |
4 | 30100000102033003 |
5 | 203414233141120 |
6 | 10013111134031 |
7 | 643645105021 |
oct | 142000221703 |
9 | 36850416181 |
10 | 13153412035 |
11 | 563a838165 |
12 | 2671074317 |
13 | 13180c695a |
14 | 8caca1711 |
15 | 51eb5740a |
hex | 3100123c3 |
13153412035 has 8 divisors (see below), whose sum is σ = 15820549920. Its totient is φ = 10498425984.
The previous prime is 13153412021. The next prime is 13153412047. The reversal of 13153412035 is 53021435131.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13153412035 - 27 = 13153411907 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13153411994 and 13153412012.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3035575 + ... + 3039904.
It is an arithmetic number, because the mean of its divisors is an integer number (1977568740).
Almost surely, 213153412035 is an apocalyptic number.
13153412035 is a deficient number, since it is larger than the sum of its proper divisors (2667137885).
13153412035 is an equidigital number, since it uses as much as digits as its factorization.
13153412035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6075917.
The product of its (nonzero) digits is 5400, while the sum is 28.
Adding to 13153412035 its reverse (53021435131), we get a palindrome (66174847166).
The spelling of 13153412035 in words is "thirteen billion, one hundred fifty-three million, four hundred twelve thousand, thirty-five".
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