131534341403 has 4 divisors (see below), whose sum is σ = 133763737080. Its totient is φ = 129304945728.

The previous prime is 131534341381. The next prime is 131534341441. The reversal of 131534341403 is 304143435131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131534341403 - 2¹⁴ = 131534325019 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131534341403.

It is not an unprimeable number, because it can be changed into a prime (131534341903) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1114697750 + ... + 1114697867.

It is an arithmetic number, because the mean of its divisors is an integer number (33440934270).

Almost surely, 2^131534341403 is an apocalyptic number.

131534341403 is a deficient number, since it is larger than the sum of its proper divisors (2229395677).

131534341403 is an equidigital number, since it uses as much as digits as its factorization.

131534341403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2229395676.

The product of its (nonzero) digits is 25920, while the sum is 32.

Adding to 131534341403 its reverse (304143435131), we get a palindrome (435677776534).

The spelling of 131534341403 in words is "one hundred thirty-one billion, five hundred thirty-four million, three hundred forty-one thousand, four hundred three".