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1315354250401 = 31173819244109
BaseRepresentation
bin10011001001000001001…
…110010000110010100001
311122202011022002012002221
4103021001032100302201
5133022321142003101
62444133154311041
7164013463436662
oct23110116206241
94582138065087
101315354250401
11467925201834
12192b11588481
13970641571c9
1447940865369
1524336db2aa1
hex13241390ca1

1315354250401 has 8 divisors (see below), whose sum is σ = 1357798406400. Its totient is φ = 1272910930320.

The previous prime is 1315354250381. The next prime is 1315354250407. The reversal of 1315354250401 is 1040524535131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1315354250401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1315354250407) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5266335 + ... + 5510443.

It is an arithmetic number, because the mean of its divisors is an integer number (169724800800).

Almost surely, 21315354250401 is an apocalyptic number.

It is an amenable number.

1315354250401 is a deficient number, since it is larger than the sum of its proper divisors (42444155999).

1315354250401 is a wasteful number, since it uses less digits than its factorization.

1315354250401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 417959.

The product of its (nonzero) digits is 36000, while the sum is 34.

Adding to 1315354250401 its reverse (1040524535131), we get a palindrome (2355878785532).

The spelling of 1315354250401 in words is "one trillion, three hundred fifteen billion, three hundred fifty-four million, two hundred fifty thousand, four hundred one".

Divisors: 1 31 173819 244109 5388389 7567379 42430782271 1315354250401