Base | Representation |
---|---|
bin | 1011111101101011110001… |
… | …1111000100010100101011 |
3 | 1201120112200102020200222120 |
4 | 2333122330133010110223 |
5 | 3211010103120334011 |
6 | 43551005334122323 |
7 | 2525241052106424 |
oct | 277327437042453 |
9 | 51515612220876 |
10 | 13154352121131 |
11 | 4211802925971 |
12 | 1585499ab03a3 |
13 | 7455b0aa5a80 |
14 | 3369617ca64b |
15 | 17c295393a06 |
hex | bf6bc7c452b |
13154352121131 has 32 divisors (see below), whose sum is σ = 18967536698880. Its totient is φ = 8061098102784.
The previous prime is 13154352121117. The next prime is 13154352121151. The reversal of 13154352121131 is 13112125345131.
It is not a de Polignac number, because 13154352121131 - 213 = 13154352112939 is a prime.
It is a super-2 number, since 2×131543521211312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13154352121092 and 13154352121101.
It is not an unprimeable number, because it can be changed into a prime (13154352121151) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8219755 + ... + 9688811.
It is an arithmetic number, because the mean of its divisors is an integer number (592735521840).
Almost surely, 213154352121131 is an apocalyptic number.
13154352121131 is a deficient number, since it is larger than the sum of its proper divisors (5813184577749).
13154352121131 is a wasteful number, since it uses less digits than its factorization.
13154352121131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1470035.
The product of its digits is 10800, while the sum is 33.
Adding to 13154352121131 its reverse (13112125345131), we get a palindrome (26266477466262).
The spelling of 13154352121131 in words is "thirteen trillion, one hundred fifty-four billion, three hundred fifty-two million, one hundred twenty-one thousand, one hundred thirty-one".
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