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1315454405051 = 4093216269939
BaseRepresentation
bin10011001001000111001…
…100010100100110111011
311122202102021112120110102
4103021013030110212323
5133023022311430201
62444151133110015
7164016120645023
oct23110714244673
94582367476412
101315454405051
11467976799476
12192b3b02830b
139707bb23207
144794dc96a83
1524340a9826b
hex132473149bb

1315454405051 has 4 divisors (see below), whose sum is σ = 1318670675400. Its totient is φ = 1312238134704.

The previous prime is 1315454405047. The next prime is 1315454405081. The reversal of 1315454405051 is 1505044545131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1315454405051 - 22 = 1315454405047 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1315454404996 and 1315454405014.

It is not an unprimeable number, because it can be changed into a prime (1315454405081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1608134561 + ... + 1608135378.

It is an arithmetic number, because the mean of its divisors is an integer number (329667668850).

Almost surely, 21315454405051 is an apocalyptic number.

1315454405051 is a deficient number, since it is larger than the sum of its proper divisors (3216270349).

1315454405051 is an equidigital number, since it uses as much as digits as its factorization.

1315454405051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3216270348.

The product of its (nonzero) digits is 120000, while the sum is 38.

The spelling of 1315454405051 in words is "one trillion, three hundred fifteen billion, four hundred fifty-four million, four hundred five thousand, fifty-one".

Divisors: 1 409 3216269939 1315454405051