Base | Representation |
---|---|
bin | 11000100000001101… |
… | …10100101100010011 |
3 | 1020221210200122101012 |
4 | 30100012310230103 |
5 | 203420203013120 |
6 | 10013212001135 |
7 | 643665504062 |
oct | 142006645423 |
9 | 36853618335 |
10 | 13155126035 |
11 | 56407a8997 |
12 | 26717601ab |
13 | 1318576b5c |
14 | 8cb1ca1d9 |
15 | 51ed951c5 |
hex | 3101b4b13 |
13155126035 has 4 divisors (see below), whose sum is σ = 15786151248. Its totient is φ = 10524100824.
The previous prime is 13155126001. The next prime is 13155126067. The reversal of 13155126035 is 53062155131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13155126035 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13155125992 and 13155126010.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1315512599 + ... + 1315512608.
It is an arithmetic number, because the mean of its divisors is an integer number (3946537812).
Almost surely, 213155126035 is an apocalyptic number.
13155126035 is a deficient number, since it is larger than the sum of its proper divisors (2631025213).
13155126035 is an equidigital number, since it uses as much as digits as its factorization.
13155126035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2631025212.
The product of its (nonzero) digits is 13500, while the sum is 32.
The spelling of 13155126035 in words is "thirteen billion, one hundred fifty-five million, one hundred twenty-six thousand, thirty-five".
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