13155315025241 has 4 divisors (see below), whose sum is σ = 13155488217984. Its totient is φ = 13155141832500.

The previous prime is 13155315025189. The next prime is 13155315025271. The reversal of 13155315025241 is 14252051355131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13155315025241 is a prime.

It is a super-2 number, since 2×13155315025241² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13155315025195 and 13155315025204.

It is not an unprimeable number, because it can be changed into a prime (13155315025271) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86482385 + ... + 86634366.

It is an arithmetic number, because the mean of its divisors is an integer number (3288872054496).

Almost surely, 2^{13155315025241} is an apocalyptic number.

It is an amenable number.

13155315025241 is a deficient number, since it is larger than the sum of its proper divisors (173192743).

13155315025241 is an equidigital number, since it uses as much as digits as its factorization.

13155315025241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 173192742.

The product of its (nonzero) digits is 90000, while the sum is 38.

The spelling of 13155315025241 in words is "thirteen trillion, one hundred fifty-five billion, three hundred fifteen million, twenty-five thousand, two hundred forty-one".