Base | Representation |
---|---|
bin | 1011111101101111101100… |
… | …0000100111101101111011 |
3 | 1201120122101112002120022020 |
4 | 2333123323000213231323 |
5 | 3211014230140314001 |
6 | 43551301405325523 |
7 | 2525306050241310 |
oct | 277337300475573 |
9 | 51518345076266 |
10 | 13155401104251 |
11 | 42121a0a6546a |
12 | 15857312668a3 |
13 | 74571a203543 |
14 | 336a20c48d07 |
15 | 17c3074ed736 |
hex | bf6fb027b7b |
13155401104251 has 32 divisors (see below), whose sum is σ = 20076247339008. Its totient is φ = 7506158315040.
The previous prime is 13155401104249. The next prime is 13155401104259. The reversal of 13155401104251 is 15240110455131.
It is not a de Polignac number, because 13155401104251 - 21 = 13155401104249 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13155401104259) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 45815736 + ... + 46101978.
It is an arithmetic number, because the mean of its divisors is an integer number (627382729344).
Almost surely, 213155401104251 is an apocalyptic number.
13155401104251 is a deficient number, since it is larger than the sum of its proper divisors (6920846234757).
13155401104251 is a wasteful number, since it uses less digits than its factorization.
13155401104251 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 289511.
The product of its (nonzero) digits is 12000, while the sum is 33.
Adding to 13155401104251 its reverse (15240110455131), we get a palindrome (28395511559382).
The spelling of 13155401104251 in words is "thirteen trillion, one hundred fifty-five billion, four hundred one million, one hundred four thousand, two hundred fifty-one".
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