Base | Representation |
---|---|
bin | 11000100000010000… |
… | …01111110101111111 |
3 | 1020221211101121112012 |
4 | 30100020033311333 |
5 | 203420301440031 |
6 | 10013224001435 |
7 | 644001620426 |
oct | 142010176577 |
9 | 36854347465 |
10 | 13155499391 |
11 | 5640a33451 |
12 | 267190027b |
13 | 1318677a88 |
14 | 8cb2862bd |
15 | 51ee1ab2b |
hex | 31020fd7f |
13155499391 has 8 divisors (see below), whose sum is σ = 13281771360. Its totient is φ = 13029666048.
The previous prime is 13155499387. The next prime is 13155499397. The reversal of 13155499391 is 19399455131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13155499391 - 22 = 13155499387 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13155499397) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 49226 + ... + 169511.
It is an arithmetic number, because the mean of its divisors is an integer number (1660221420).
Almost surely, 213155499391 is an apocalyptic number.
13155499391 is a deficient number, since it is larger than the sum of its proper divisors (126271969).
13155499391 is a wasteful number, since it uses less digits than its factorization.
13155499391 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 219313.
The product of its digits is 656100, while the sum is 50.
The spelling of 13155499391 in words is "thirteen billion, one hundred fifty-five million, four hundred ninety-nine thousand, three hundred ninety-one".
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