Base | Representation |
---|---|
bin | 11000100000010011… |
… | …01010101111111101 |
3 | 1020221212002112021221 |
4 | 30100021222233331 |
5 | 203420400343431 |
6 | 10013235553341 |
7 | 644005031125 |
oct | 142011525775 |
9 | 36855075257 |
10 | 13155871741 |
11 | 5641168181 |
12 | 2671a5b851 |
13 | 13187783bc |
14 | 8cb341c85 |
15 | 51ee91111 |
hex | 31026abfd |
13155871741 has 4 divisors (see below), whose sum is σ = 13156148572. Its totient is φ = 13155594912.
The previous prime is 13155871727. The next prime is 13155871783. The reversal of 13155871741 is 14717855131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 2462243641 + 10693628100 = 49621^2 + 103410^2 .
It is a cyclic number.
It is not a de Polignac number, because 13155871741 - 27 = 13155871613 is a prime.
It is a super-2 number, since 2×131558717412 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13155871711) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47010 + ... + 168883.
It is an arithmetic number, because the mean of its divisors is an integer number (3289037143).
Almost surely, 213155871741 is an apocalyptic number.
It is an amenable number.
13155871741 is a deficient number, since it is larger than the sum of its proper divisors (276831).
13155871741 is an equidigital number, since it uses as much as digits as its factorization.
13155871741 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 276830.
The product of its digits is 117600, while the sum is 43.
The spelling of 13155871741 in words is "thirteen billion, one hundred fifty-five million, eight hundred seventy-one thousand, seven hundred forty-one".
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