Base | Representation |
---|---|
bin | 1011111101110011011111… |
… | …1001011010011101110011 |
3 | 1201120202000201021012112012 |
4 | 2333130313321122131303 |
5 | 3211023323143001024 |
6 | 43551551020153135 |
7 | 2525343263104313 |
oct | 277346771323563 |
9 | 51522021235465 |
10 | 13156422625139 |
11 | 4212675648202 |
12 | 15859773987ab |
13 | 745850a37181 |
14 | 336aba799443 |
15 | 17c36703150e |
hex | bf737e5a773 |
13156422625139 has 4 divisors (see below), whose sum is σ = 13173139808424. Its totient is φ = 13139705441856.
The previous prime is 13156422625081. The next prime is 13156422625141. The reversal of 13156422625139 is 93152622465131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13156422625139 - 240 = 12056910997363 is a prime.
It is a super-2 number, since 2×131564226251392 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13156422615139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8358590462 + ... + 8358592035.
It is an arithmetic number, because the mean of its divisors is an integer number (3293284952106).
Almost surely, 213156422625139 is an apocalyptic number.
13156422625139 is a deficient number, since it is larger than the sum of its proper divisors (16717183285).
13156422625139 is an equidigital number, since it uses as much as digits as its factorization.
13156422625139 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16717183284.
The product of its digits is 2332800, while the sum is 50.
The spelling of 13156422625139 in words is "thirteen trillion, one hundred fifty-six billion, four hundred twenty-two million, six hundred twenty-five thousand, one hundred thirty-nine".
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