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13156422625141 is a prime number
BaseRepresentation
bin1011111101110011011111…
…1001011010011101110101
31201120202000201021012112021
42333130313321122131311
53211023323143001031
643551551020153141
72525343263104315
oct277346771323565
951522021235467
1013156422625141
114212675648204
1215859773987b1
13745850a37183
14336aba799445
1517c367031511
hexbf737e5a775

13156422625141 has 2 divisors, whose sum is σ = 13156422625142. Its totient is φ = 13156422625140.

The previous prime is 13156422625081. The next prime is 13156422625201. The reversal of 13156422625141 is 14152622465131.

It is a balanced prime because it is at equal distance from previous prime (13156422625081) and next prime (13156422625201).

It can be written as a sum of positive squares in only one way, i.e., 11969039736900 + 1187382888241 = 3459630^2 + 1089671^2 .

It is a cyclic number.

It is not a de Polignac number, because 13156422625141 - 215 = 13156422592373 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13156422625441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6578211312570 + 6578211312571.

It is an arithmetic number, because the mean of its divisors is an integer number (6578211312571).

Almost surely, 213156422625141 is an apocalyptic number.

It is an amenable number.

13156422625141 is a deficient number, since it is larger than the sum of its proper divisors (1).

13156422625141 is an equidigital number, since it uses as much as digits as its factorization.

13156422625141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 345600, while the sum is 43.

The spelling of 13156422625141 in words is "thirteen trillion, one hundred fifty-six billion, four hundred twenty-two million, six hundred twenty-five thousand, one hundred forty-one".