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131565054352117 = 400579328437223
BaseRepresentation
bin11101111010100001100000…
…010101000101101011110101
3122020211111101211212220220011
4131322201200111011223311
5114221030212403231432
61143452052424140221
736466155460204261
oct3572414025055365
9566744354786804
10131565054352117
1138a14476319191
121290a232607671
1358546ba607869
14246bad568b0a1
151032497c86847
hex77a860545af5

131565054352117 has 4 divisors (see below), whose sum is σ = 131565383189920. Its totient is φ = 131564725514316.

The previous prime is 131565054352091. The next prime is 131565054352133. The reversal of 131565054352117 is 711253450565131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131565054352117 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131565054952117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 163818033 + ... + 164619190.

It is an arithmetic number, because the mean of its divisors is an integer number (32891345797480).

Almost surely, 2131565054352117 is an apocalyptic number.

It is an amenable number.

131565054352117 is a deficient number, since it is larger than the sum of its proper divisors (328837803).

131565054352117 is an equidigital number, since it uses as much as digits as its factorization.

131565054352117 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 328837802.

The product of its (nonzero) digits is 1890000, while the sum is 49.

The spelling of 131565054352117 in words is "one hundred thirty-one trillion, five hundred sixty-five billion, fifty-four million, three hundred fifty-two thousand, one hundred seventeen".

Divisors: 1 400579 328437223 131565054352117