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1316051113145 = 52311443922723
BaseRepresentation
bin10011001001101010110…
…000100101010010111001
311122210221212100111002012
4103021222300211102321
5133030233041110040
62444330250415305
7164036654613536
oct23115260452271
94583855314065
101316051113145
114681525a905a
12193086a31535
1397145638622
14479a9223d8d
1524378165865
hex1326ac254b9

1316051113145 has 8 divisors (see below), whose sum is σ = 1647924872256. Its totient is φ = 1007065199536.

The previous prime is 1316051113133. The next prime is 1316051113207. The reversal of 1316051113145 is 5413111506131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1316051113145 - 24 = 1316051113129 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5721961247 + ... + 5721961476.

It is an arithmetic number, because the mean of its divisors is an integer number (205990609032).

Almost surely, 21316051113145 is an apocalyptic number.

It is an amenable number.

1316051113145 is a deficient number, since it is larger than the sum of its proper divisors (331873759111).

1316051113145 is a wasteful number, since it uses less digits than its factorization.

1316051113145 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11443922751.

The product of its (nonzero) digits is 5400, while the sum is 32.

Adding to 1316051113145 its reverse (5413111506131), we get a palindrome (6729162619276).

The spelling of 1316051113145 in words is "one trillion, three hundred sixteen billion, fifty-one million, one hundred thirteen thousand, one hundred forty-five".

Divisors: 1 5 23 115 11443922723 57219613615 263210222629 1316051113145