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1316100340083 = 3438700113361
BaseRepresentation
bin10011001001101101101…
…100010111100101110011
311122211002021222110202010
4103021231230113211303
5133030333141340313
62444335205454003
7164041123211364
oct23115554274563
94584067873663
101316100340083
11468178370a81
1219309b411303
13971528b2ba9
14479b1999b6b
152437c63b4c3
hex1326db17973

1316100340083 has 4 divisors (see below), whose sum is σ = 1754800453448. Its totient is φ = 877400226720.

The previous prime is 1316100340073. The next prime is 1316100340097. The reversal of 1316100340083 is 3800430016131.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1316100340083 - 24 = 1316100340067 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1316100340083.

It is not an unprimeable number, because it can be changed into a prime (1316100340073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 219350056678 + ... + 219350056683.

It is an arithmetic number, because the mean of its divisors is an integer number (438700113362).

Almost surely, 21316100340083 is an apocalyptic number.

1316100340083 is a deficient number, since it is larger than the sum of its proper divisors (438700113365).

1316100340083 is an equidigital number, since it uses as much as digits as its factorization.

1316100340083 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 438700113364.

The product of its (nonzero) digits is 5184, while the sum is 30.

The spelling of 1316100340083 in words is "one trillion, three hundred sixteen billion, one hundred million, three hundred forty thousand, eighty-three".

Divisors: 1 3 438700113361 1316100340083