1316425314333 has 4 divisors (see below), whose sum is σ = 1755233752448. Its totient is φ = 877616876220.

The previous prime is 1316425314311. The next prime is 1316425314341. The reversal of 1316425314333 is 3334135246131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1316425314333 - 2⁵ = 1316425314301 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1316425314291 and 1316425314300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1316425314433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 219404219053 + ... + 219404219058.

It is an arithmetic number, because the mean of its divisors is an integer number (438808438112).

Almost surely, 2^{1316425314333} is an apocalyptic number.

It is an amenable number.

1316425314333 is a deficient number, since it is larger than the sum of its proper divisors (438808438115).

1316425314333 is an equidigital number, since it uses as much as digits as its factorization.

1316425314333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 438808438114.

The product of its digits is 233280, while the sum is 39.

The spelling of 1316425314333 in words is "one trillion, three hundred sixteen billion, four hundred twenty-five million, three hundred fourteen thousand, three hundred thirty-three".