Search a number
-
+
1316605413001 = 2834652315947
BaseRepresentation
bin10011001010001011110…
…011000100011010001001
311122212101111100211112111
4103022023303010122021
5133032401441204001
62444501251142321
7164056465234234
oct23121363043211
94585344324474
101316605413001
1146840748280a
121932005a49a1
1397203422cc8
1447a1cab241b
15243abb57851
hex1328bcc4689

1316605413001 has 4 divisors (see below), whose sum is σ = 1321257729232. Its totient is φ = 1311953096772.

The previous prime is 1316605412999. The next prime is 1316605413017. The reversal of 1316605413001 is 1003145066131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1316605413001 - 21 = 1316605412999 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1316605413031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2326157691 + ... + 2326158256.

It is an arithmetic number, because the mean of its divisors is an integer number (330314432308).

Almost surely, 21316605413001 is an apocalyptic number.

It is an amenable number.

1316605413001 is a deficient number, since it is larger than the sum of its proper divisors (4652316231).

1316605413001 is an equidigital number, since it uses as much as digits as its factorization.

1316605413001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4652316230.

The product of its (nonzero) digits is 6480, while the sum is 31.

The spelling of 1316605413001 in words is "one trillion, three hundred sixteen billion, six hundred five million, four hundred thirteen thousand, one".

Divisors: 1 283 4652315947 1316605413001