Base | Representation |
---|---|
bin | 1011111110011001100101… |
… | …1111111111111011101111 |
3 | 1201121201102110222221222011 |
4 | 2333212121133333323233 |
5 | 3211210244404031443 |
6 | 44000401525502051 |
7 | 2526154601646166 |
oct | 277463137777357 |
9 | 51551373887864 |
10 | 13166650064623 |
11 | 4216a43786930 |
12 | 1587950571927 |
13 | 7467c0898303 |
14 | 3373aac043dd |
15 | 17c764d68b9d |
hex | bf9997ffeef |
13166650064623 has 4 divisors (see below), whose sum is σ = 14363618252328. Its totient is φ = 11969681876920.
The previous prime is 13166650064591. The next prime is 13166650064641. The reversal of 13166650064623 is 32646005666131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13166650064623 - 25 = 13166650064591 is a prime.
It is a super-2 number, since 2×131666500646232 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13166650064653) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 598484093836 + ... + 598484093857.
It is an arithmetic number, because the mean of its divisors is an integer number (3590904563082).
Almost surely, 213166650064623 is an apocalyptic number.
13166650064623 is a deficient number, since it is larger than the sum of its proper divisors (1196968187705).
13166650064623 is a wasteful number, since it uses less digits than its factorization.
13166650064623 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1196968187704.
The product of its (nonzero) digits is 2799360, while the sum is 49.
The spelling of 13166650064623 in words is "thirteen trillion, one hundred sixty-six billion, six hundred fifty million, sixty-four thousand, six hundred twenty-three".
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