1317040121 has 4 divisors (see below), whose sum is σ = 1317251472. Its totient is φ = 1316828772.

The previous prime is 1317040103. The next prime is 1317040129. The reversal of 1317040121 is 1210407131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1317040121 - 2⁶ = 1317040057 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1317040093 and 1317040102.

It is not an unprimeable number, because it can be changed into a prime (1317040129) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 96035 + ... + 108888.

It is an arithmetic number, because the mean of its divisors is an integer number (329312868).

Almost surely, 2^1317040121 is an apocalyptic number.

It is an amenable number.

1317040121 is a deficient number, since it is larger than the sum of its proper divisors (211351).

1317040121 is an equidigital number, since it uses as much as digits as its factorization.

1317040121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 211350.

The product of its (nonzero) digits is 168, while the sum is 20.

The square root of 1317040121 is about 36291.0473946399. The cubic root of 1317040121 is about 1096.1407795192.

Adding to 1317040121 its reverse (1210407131), we get a palindrome (2527447252).

The spelling of 1317040121 in words is "one billion, three hundred seventeen million, forty thousand, one hundred twenty-one".