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1317251105663 = 6173213389131
BaseRepresentation
bin10011001010110010010…
…010001100001101111111
311122221001111100102100112
4103022302102030031333
5133040212240340123
62445045314420235
7164111465441153
oct23126222141577
94587044312315
101317251105663
114687089aa209
1219336089167b
13972a712957c
1447a80751063
15243e869dd78
hex132b248c37f

1317251105663 has 4 divisors (see below), whose sum is σ = 1317464500968. Its totient is φ = 1317037710360.

The previous prime is 1317251105647. The next prime is 1317251105711. The reversal of 1317251105663 is 3665011527131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1317251105663 - 24 = 1317251105647 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1317251105663.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1317251105063) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 106688393 + ... + 106700738.

It is an arithmetic number, because the mean of its divisors is an integer number (329366125242).

Almost surely, 21317251105663 is an apocalyptic number.

1317251105663 is a deficient number, since it is larger than the sum of its proper divisors (213395305).

1317251105663 is an equidigital number, since it uses as much as digits as its factorization.

1317251105663 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 213395304.

The product of its (nonzero) digits is 113400, while the sum is 41.

The spelling of 1317251105663 in words is "one trillion, three hundred seventeen billion, two hundred fifty-one million, one hundred five thousand, six hundred sixty-three".

Divisors: 1 6173 213389131 1317251105663