Base | Representation |
---|---|
bin | 111101010110010001… |
… | …0101010000010001111 |
3 | 110121001110011201002021 |
4 | 1322230202222002033 |
5 | 4124302402110403 |
6 | 140304450311011 |
7 | 12342506460640 |
oct | 1725442520217 |
9 | 417043151067 |
10 | 131743785103 |
11 | 50965a28747 |
12 | 21648888467 |
13 | c567241738 |
14 | 653ad0b6c7 |
15 | 3660eb58bd |
hex | 1eac8aa08f |
131743785103 has 4 divisors (see below), whose sum is σ = 150564325840. Its totient is φ = 112923244368.
The previous prime is 131743785101. The next prime is 131743785137. The reversal of 131743785103 is 301587347131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131743785103 - 21 = 131743785101 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 131743785103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131743785101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9410270358 + ... + 9410270371.
It is an arithmetic number, because the mean of its divisors is an integer number (37641081460).
Almost surely, 2131743785103 is an apocalyptic number.
131743785103 is a deficient number, since it is larger than the sum of its proper divisors (18820540737).
131743785103 is an equidigital number, since it uses as much as digits as its factorization.
131743785103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18820540736.
The product of its (nonzero) digits is 211680, while the sum is 43.
The spelling of 131743785103 in words is "one hundred thirty-one billion, seven hundred forty-three million, seven hundred eighty-five thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •