Base | Representation |
---|---|
bin | 11101111101001000001101… |
… | …100110100101010011011111 |
3 | 122021110121102201021211000002 |
4 | 131331020031212211103133 |
5 | 114231443311043234313 |
6 | 1144110214450324515 |
7 | 36515123333113355 |
oct | 3575101546452337 |
9 | 567417381254002 |
10 | 131744055055583 |
11 | 38a83381578063 |
12 | 12938a6958973b |
13 | 58685461ca189 |
14 | 247663687d7d5 |
15 | 1036e7289c058 |
hex | 77d20d9a54df |
131744055055583 has 4 divisors (see below), whose sum is σ = 137472057449328. Its totient is φ = 126016052661840.
The previous prime is 131744055055577. The next prime is 131744055055589. The reversal of 131744055055583 is 385550550447131.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (131744055055577) and next prime (131744055055589).
It is a cyclic number.
It is not a de Polignac number, because 131744055055583 - 214 = 131744055039199 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131744055055589) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2864001196838 + ... + 2864001196883.
It is an arithmetic number, because the mean of its divisors is an integer number (34368014362332).
Almost surely, 2131744055055583 is an apocalyptic number.
131744055055583 is a deficient number, since it is larger than the sum of its proper divisors (5728002393745).
131744055055583 is an equidigital number, since it uses as much as digits as its factorization.
131744055055583 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5728002393744.
The product of its (nonzero) digits is 25200000, while the sum is 56.
The spelling of 131744055055583 in words is "one hundred thirty-one trillion, seven hundred forty-four billion, fifty-five million, fifty-five thousand, five hundred eighty-three".
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