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131981061741 = 343993687247
BaseRepresentation
bin111101011101010101…
…1110010111001101101
3110121122222122121102220
41322322223302321231
54130244122433431
6140344204105553
712351420341364
oct1727253627155
9417588577386
10131981061741
1150a77961141
12216b42352b9
13c5a444ab09
1465606347db
153676c34b96
hex1ebaaf2e6d

131981061741 has 4 divisors (see below), whose sum is σ = 175974748992. Its totient is φ = 87987374492.

The previous prime is 131981061727. The next prime is 131981061781. The reversal of 131981061741 is 147160189131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131981061741 - 213 = 131981053549 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131981061693 and 131981061702.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131981061701) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21996843621 + ... + 21996843626.

It is an arithmetic number, because the mean of its divisors is an integer number (43993687248).

Almost surely, 2131981061741 is an apocalyptic number.

It is an amenable number.

131981061741 is a deficient number, since it is larger than the sum of its proper divisors (43993687251).

131981061741 is an equidigital number, since it uses as much as digits as its factorization.

131981061741 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43993687250.

The product of its (nonzero) digits is 36288, while the sum is 42.

The spelling of 131981061741 in words is "one hundred thirty-one billion, nine hundred eighty-one million, sixty-one thousand, seven hundred forty-one".

Divisors: 1 3 43993687247 131981061741