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132000031304234 = 266000015652117
BaseRepresentation
bin11110000000110110100110…
…111110011110101000101010
3122022101002011010202120001222
4132000312212332132220222
5114300142031003213414
61144423551025542042
736542454554246522
oct3600664676365052
9568332133676058
10132000031304234
113907199848a385
121297a5a74a4922
13588671b45a072
142484b9ac7a682
15103d9551ab68e
hex780da6f9ea2a

132000031304234 has 4 divisors (see below), whose sum is σ = 198000046956354. Its totient is φ = 66000015652116.

The previous prime is 132000031304231. The next prime is 132000031304257. The reversal of 132000031304234 is 432403130000231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 86639738954209 + 45360292350025 = 9308047^2 + 6735005^2 .

It is not an unprimeable number, because it can be changed into a prime (132000031304231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33000007826057 + ... + 33000007826060.

Almost surely, 2132000031304234 is an apocalyptic number.

132000031304234 is a deficient number, since it is larger than the sum of its proper divisors (66000015652120).

132000031304234 is an equidigital number, since it uses as much as digits as its factorization.

132000031304234 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66000015652119.

The product of its (nonzero) digits is 5184, while the sum is 26.

Adding to 132000031304234 its reverse (432403130000231), we get a palindrome (564403161304465).

The spelling of 132000031304234 in words is "one hundred thirty-two trillion, thirty-one million, three hundred four thousand, two hundred thirty-four".

Divisors: 1 2 66000015652117 132000031304234