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132000100310021 = 226435829620647
BaseRepresentation
bin11110000000110110101011…
…000101101101110000000101
3122022101002022221121102012212
4132000312223011231300011
5114300142201134410041
61144424001532553205
736542456352632546
oct3600665305556005
9568332287542185
10132000100310021
1139071a23431459
121297a606622805
13588672c83b1a8
142484ba60c04cd
15103d95b28c8eb
hex780dab16dc05

132000100310021 has 4 divisors (see below), whose sum is σ = 132005929953312. Its totient is φ = 131994270666732.

The previous prime is 132000100310011. The next prime is 132000100310059. The reversal of 132000100310021 is 120013001000231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132000100310021 is a prime.

It is a super-2 number, since 2×1320001003100212 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 132000100309978 and 132000100310005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132000100310011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2914787681 + ... + 2914832966.

It is an arithmetic number, because the mean of its divisors is an integer number (33001482488328).

Almost surely, 2132000100310021 is an apocalyptic number.

It is an amenable number.

132000100310021 is a deficient number, since it is larger than the sum of its proper divisors (5829643291).

132000100310021 is an equidigital number, since it uses as much as digits as its factorization.

132000100310021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5829643290.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 132000100310021 its reverse (120013001000231), we get a palindrome (252013101310252).

The spelling of 132000100310021 in words is "one hundred thirty-two trillion, one hundred million, three hundred ten thousand, twenty-one".

Divisors: 1 22643 5829620647 132000100310021