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132000121023 = 344000040341
BaseRepresentation
bin111101011101111010…
…0100000000010111111
3110121201022111220212020
41322323310200002333
54130314012333043
6140350124411223
712352041341661
oct1727364400277
9417638456766
10132000121023
1150a87699711
12216ba6a6b13
13c5a8391cb4
146562d96531
15367874be83
hex1ebbd200bf

132000121023 has 4 divisors (see below), whose sum is σ = 176000161368. Its totient is φ = 88000080680.

The previous prime is 132000121007. The next prime is 132000121049. The reversal of 132000121023 is 320121000231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132000121023 - 24 = 132000121007 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132000120993 and 132000121011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132000121093) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22000020168 + ... + 22000020173.

It is an arithmetic number, because the mean of its divisors is an integer number (44000040342).

Almost surely, 2132000121023 is an apocalyptic number.

132000121023 is a deficient number, since it is larger than the sum of its proper divisors (44000040345).

132000121023 is an equidigital number, since it uses as much as digits as its factorization.

132000121023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44000040344.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 132000121023 its reverse (320121000231), we get a palindrome (452121121254).

The spelling of 132000121023 in words is "one hundred thirty-two billion, one hundred twenty-one thousand, twenty-three".

Divisors: 1 3 44000040341 132000121023