132000240140021 has 4 divisors (see below), whose sum is σ = 144000261970944. Its totient is φ = 120000218309100.

The previous prime is 132000240139921. The next prime is 132000240140107. The reversal of 132000240140021 is 120041042000231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-132000240140021 is a prime.

It is a super-2 number, since 2×132000240140021² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132000240139975 and 132000240140002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132000240140921) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6000010915445 + ... + 6000010915466.

It is an arithmetic number, because the mean of its divisors is an integer number (36000065492736).

Almost surely, 2^{132000240140021} is an apocalyptic number.

132000240140021 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

132000240140021 is a deficient number, since it is larger than the sum of its proper divisors (12000021830923).

132000240140021 is a wasteful number, since it uses less digits than its factorization.

132000240140021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12000021830922.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 132000240140021 its reverse (120041042000231), we get a palindrome (252041282140252).

The spelling of 132000240140021 in words is "one hundred thirty-two trillion, two hundred forty million, one hundred forty thousand, twenty-one".