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1320003000131 = 1604998224369
BaseRepresentation
bin10011001101010110010…
…011110101011101000011
311200012011021112010212212
4103031112103311131003
5133111331232001011
62450222341212335
7164236622242124
oct23152623653503
94605137463785
101320003000131
114698a0310262
121939aa4010ab
13976252b27aa
1447c6201204b
152450a08508b
hex133564f5743

1320003000131 has 4 divisors (see below), whose sum is σ = 1320011385000. Its totient is φ = 1319994615264.

The previous prime is 1320003000077. The next prime is 1320003000137. The reversal of 1320003000131 is 1310003000231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1320003000131 is a prime.

It is a super-2 number, since 2×13200030001312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1320003000137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3951686 + ... + 4272683.

It is an arithmetic number, because the mean of its divisors is an integer number (330002846250).

Almost surely, 21320003000131 is an apocalyptic number.

1320003000131 is a deficient number, since it is larger than the sum of its proper divisors (8384869).

1320003000131 is an equidigital number, since it uses as much as digits as its factorization.

1320003000131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8384868.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 1320003000131 its reverse (1310003000231), we get a palindrome (2630006000362).

The spelling of 1320003000131 in words is "one trillion, three hundred twenty billion, three million, one hundred thirty-one", and thus it is an aban number.

Divisors: 1 160499 8224369 1320003000131