Base | Representation |
---|---|
bin | 10011000100000010010… |
… | …000110111001110100111 |
3 | 11122020100100202111220012 |
4 | 103010002100313032213 |
5 | 132430341232001411 |
6 | 2441450154400435 |
7 | 163434044530352 |
oct | 23040220671647 |
9 | 4566310674805 |
10 | 1310003000231 |
11 | 4656295a6332 |
12 | 191a7943011b |
13 | 966c05c53a3 |
14 | 47593c8d299 |
15 | 241221c718b |
hex | 131024373a7 |
1310003000231 has 2 divisors, whose sum is σ = 1310003000232. Its totient is φ = 1310003000230.
The previous prime is 1310003000219. The next prime is 1310003000237. The reversal of 1310003000231 is 1320003000131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1310003000231 is a prime.
It is a super-2 number, since 2×13100030002312 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310003000237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655001500115 + 655001500116.
It is an arithmetic number, because the mean of its divisors is an integer number (655001500116).
Almost surely, 21310003000231 is an apocalyptic number.
1310003000231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310003000231 is an equidigital number, since it uses as much as digits as its factorization.
1310003000231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 1310003000231 its reverse (1320003000131), we get a palindrome (2630006000362).
The spelling of 1310003000231 in words is "one trillion, three hundred ten billion, three million, two hundred thirty-one", and thus it is an aban number.
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