13200031000301 has 4 divisors (see below), whose sum is σ = 13655204483100. Its totient is φ = 12744857517504.

The previous prime is 13200031000283. The next prime is 13200031000307. The reversal of 13200031000301 is 10300013000231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5180968078276 + 8019062922025 = 2276174^2 + 2831795^2 .

It is a cyclic number.

It is not a de Polignac number, because 13200031000301 - 2¹⁴ = 13200030983917 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13200031000307) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 227586741356 + ... + 227586741413.

It is an arithmetic number, because the mean of its divisors is an integer number (3413801120775).

Almost surely, 2^{13200031000301} is an apocalyptic number.

It is an amenable number.

13200031000301 is a deficient number, since it is larger than the sum of its proper divisors (455173482799).

13200031000301 is an equidigital number, since it uses as much as digits as its factorization.

13200031000301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 455173482798.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 13200031000301 its reverse (10300013000231), we get a palindrome (23500044000532).

The spelling of 13200031000301 in words is "thirteen trillion, two hundred billion, thirty-one million, three hundred one", and thus it is an aban number.