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1320004102031 = 231911159325919
BaseRepresentation
bin10011001101010110011…
…000000010011110001111
311200012011100121010101222
4103031112120002132033
5133111332022231111
62450222420553555
7164236634511506
oct23152630023617
94605140533358
101320004102031
114698a09a311a
121939aa8528bb
13976255aa1c4
1447c6221b83d
152450a2017db
hex1335660278f

1320004102031 has 16 divisors (see below), whose sum is σ = 1384779939840. Its totient is φ = 1255845286080.

The previous prime is 1320004102019. The next prime is 1320004102037. The reversal of 1320004102031 is 1302014000231.

It is a de Polignac number, because none of the positive numbers 2k-1320004102031 is a prime.

It is a super-2 number, since 2×13200041020312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1320004102037) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 50915090 + ... + 50941008.

It is an arithmetic number, because the mean of its divisors is an integer number (86548746240).

Almost surely, 21320004102031 is an apocalyptic number.

1320004102031 is a deficient number, since it is larger than the sum of its proper divisors (64775837809).

1320004102031 is a wasteful number, since it uses less digits than its factorization.

1320004102031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37726.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 1320004102031 its reverse (1302014000231), we get a palindrome (2622018102262).

The spelling of 1320004102031 in words is "one trillion, three hundred twenty billion, four million, one hundred two thousand, thirty-one".

Divisors: 1 23 191 4393 11593 25919 266639 596137 2214263 4950529 50928049 113862167 300478967 6911016241 57391482697 1320004102031