Base | Representation |
---|---|
bin | 10011001101010110011… |
… | …000001011111111000111 |
3 | 11200012011100200002212020 |
4 | 103031112120023333013 |
5 | 133111332030002444 |
6 | 2450222421454223 |
7 | 164236635033225 |
oct | 23152630137707 |
9 | 4605140602766 |
10 | 1320004140999 |
11 | 4698a0a1a425 |
12 | 1939aa871373 |
13 | 976255c1b6b |
14 | 47c6222bb15 |
15 | 2450a20d119 |
hex | 1335660bfc7 |
1320004140999 has 4 divisors (see below), whose sum is σ = 1760005521336. Its totient is φ = 880002760664.
The previous prime is 1320004140913. The next prime is 1320004141009. The reversal of 1320004140999 is 9990414000231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1320004140999 - 28 = 1320004140743 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1320004140999.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1320004140199) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 220000690164 + ... + 220000690169.
It is an arithmetic number, because the mean of its divisors is an integer number (440001380334).
Almost surely, 21320004140999 is an apocalyptic number.
1320004140999 is a deficient number, since it is larger than the sum of its proper divisors (440001380337).
1320004140999 is an equidigital number, since it uses as much as digits as its factorization.
1320004140999 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 440001380336.
The product of its (nonzero) digits is 69984, while the sum is 42.
The spelling of 1320004140999 in words is "one trillion, three hundred twenty billion, four million, one hundred forty thousand, nine hundred ninety-nine".
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