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1320010200211 = 2481195320069
BaseRepresentation
bin10011001101010110101…
…111010011010010010011
311200012011210001221112111
4103031112233103102103
5133111340102401321
62450223155410151
7164240040400453
oct23152657232223
94605153057474
101320010200211
114698a438883a
121939b08b3957
1397626933ab1
1447c62d67d63
152450aa085e1
hex13356bd3493

1320010200211 has 4 divisors (see below), whose sum is σ = 1320015768400. Its totient is φ = 1320004632024.

The previous prime is 1320010200199. The next prime is 1320010200227. The reversal of 1320010200211 is 1120020100231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1320010200211 - 239 = 770254386323 is a prime.

It is a super-2 number, since 2×13200102002112 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1320010200191 and 1320010200200.

It is not an unprimeable number, because it can be changed into a prime (1320010200241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2411916 + ... + 2908153.

It is an arithmetic number, because the mean of its divisors is an integer number (330003942100).

Almost surely, 21320010200211 is an apocalyptic number.

1320010200211 is a deficient number, since it is larger than the sum of its proper divisors (5568189).

1320010200211 is an equidigital number, since it uses as much as digits as its factorization.

1320010200211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5568188.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 1320010200211 its reverse (1120020100231), we get a palindrome (2440030300442).

The spelling of 1320010200211 in words is "one trillion, three hundred twenty billion, ten million, two hundred thousand, two hundred eleven".

Divisors: 1 248119 5320069 1320010200211