1320010320021 has 4 divisors (see below), whose sum is σ = 1760013760032. Its totient is φ = 880006880012.

The previous prime is 1320010320001. The next prime is 1320010320133. The reversal of 1320010320021 is 1200230100231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1320010320021 - 2¹¹ = 1320010317973 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1320010320001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 220001720001 + ... + 220001720006.

It is an arithmetic number, because the mean of its divisors is an integer number (440003440008).

Almost surely, 2^{1320010320021} is an apocalyptic number.

It is an amenable number.

1320010320021 is a deficient number, since it is larger than the sum of its proper divisors (440003440011).

1320010320021 is an equidigital number, since it uses as much as digits as its factorization.

1320010320021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 440003440010.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 1320010320021 its reverse (1200230100231), we get a palindrome (2520240420252).

The spelling of 1320010320021 in words is "one trillion, three hundred twenty billion, ten million, three hundred twenty thousand, twenty-one".