13200143311123 has 4 divisors (see below), whose sum is σ = 13202504279568. Its totient is φ = 13197782342680.

The previous prime is 13200143311097. The next prime is 13200143311127. The reversal of 13200143311123 is 32111334100231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13200143311123 is a prime.

It is a super-2 number, since 2×13200143311123² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13200143311127) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1180475836 + ... + 1180487017.

It is an arithmetic number, because the mean of its divisors is an integer number (3300626069892).

Almost surely, 2^{13200143311123} is an apocalyptic number.

13200143311123 is a deficient number, since it is larger than the sum of its proper divisors (2360968445).

13200143311123 is an equidigital number, since it uses as much as digits as its factorization.

13200143311123 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2360968444.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 13200143311123 its reverse (32111334100231), we get a palindrome (45311477411354).

The spelling of 13200143311123 in words is "thirteen trillion, two hundred billion, one hundred forty-three million, three hundred eleven thousand, one hundred twenty-three".