Base | Representation |
---|---|
bin | 11000100101100101… |
… | …10011100100100011 |
3 | 1021001221112011020111 |
4 | 30102302303210203 |
5 | 204013223211321 |
6 | 10021502152151 |
7 | 645053635606 |
oct | 142262634443 |
9 | 37057464214 |
10 | 13200210211 |
11 | 56641a1341 |
12 | 2684882657 |
13 | 1324a00896 |
14 | 8d31a433d |
15 | 523ced5e1 |
hex | 312cb3923 |
13200210211 has 4 divisors (see below), whose sum is σ = 13201515432. Its totient is φ = 13198904992.
The previous prime is 13200210193. The next prime is 13200210217. The reversal of 13200210211 is 11201200231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13200210211 - 29 = 13200209699 is a prime.
It is a super-2 number, since 2×132002102112 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13200210191 and 13200210200.
It is not an unprimeable number, because it can be changed into a prime (13200210217) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 637321 + ... + 657706.
It is an arithmetic number, because the mean of its divisors is an integer number (3300378858).
Almost surely, 213200210211 is an apocalyptic number.
13200210211 is a deficient number, since it is larger than the sum of its proper divisors (1305221).
13200210211 is a wasteful number, since it uses less digits than its factorization.
13200210211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1305220.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 13200210211 its reverse (11201200231), we get a palindrome (24401410442).
The spelling of 13200210211 in words is "thirteen billion, two hundred million, two hundred ten thousand, two hundred eleven".
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