Base | Representation |
---|---|
bin | 11000100101100101… |
… | …10100000000110011 |
3 | 1021001221112020201110 |
4 | 30102302310000303 |
5 | 204013223241034 |
6 | 10021502204403 |
7 | 645053644101 |
oct | 142262640063 |
9 | 37057466643 |
10 | 13200212019 |
11 | 56641a2735 |
12 | 2684883703 |
13 | 1324a01657 |
14 | 8d31a4c71 |
15 | 523cedde9 |
hex | 312cb4033 |
13200212019 has 32 divisors (see below), whose sum is σ = 19042560000. Its totient is φ = 8105163264.
The previous prime is 13200211991. The next prime is 13200212027. The reversal of 13200212019 is 91021200231.
It is not a de Polignac number, because 13200212019 - 28 = 13200211763 is a prime.
It is a super-2 number, since 2×132002120192 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13200211986 and 13200212004.
It is not an unprimeable number, because it can be changed into a prime (13200212089) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5058187 + ... + 5060795.
It is an arithmetic number, because the mean of its divisors is an integer number (595080000).
Almost surely, 213200212019 is an apocalyptic number.
13200212019 is a gapful number since it is divisible by the number (19) formed by its first and last digit.
13200212019 is a deficient number, since it is larger than the sum of its proper divisors (5842347981).
13200212019 is a wasteful number, since it uses less digits than its factorization.
13200212019 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5067.
The product of its (nonzero) digits is 216, while the sum is 21.
The spelling of 13200212019 in words is "thirteen billion, two hundred million, two hundred twelve thousand, nineteen".
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