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132002311202003 = 1112000210109273
BaseRepresentation
bin11110000000111000101110…
…110111100110010011010011
3122022101022001000210100212002
4132000320232313212103103
5114300211213131431003
61144425005152024215
736542565220125014
oct3600705667462323
9568338030710762
10132002311202003
1139072958420310
121297ab22b3206b
1358869c28b43b8
142484d3599500b
15103da3a40ba88
hex780e2ede64d3

132002311202003 has 4 divisors (see below), whose sum is σ = 144002521311288. Its totient is φ = 120002101092720.

The previous prime is 132002311201993. The next prime is 132002311202017. The reversal of 132002311202003 is 300202113200231.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 132002311202003 - 210 = 132002311200979 is a prime.

It is a super-2 number, since 2×1320023112020032 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132002311202303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6000105054626 + ... + 6000105054647.

It is an arithmetic number, because the mean of its divisors is an integer number (36000630327822).

Almost surely, 2132002311202003 is an apocalyptic number.

132002311202003 is a deficient number, since it is larger than the sum of its proper divisors (12000210109285).

132002311202003 is a wasteful number, since it uses less digits than its factorization.

132002311202003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12000210109284.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 132002311202003 its reverse (300202113200231), we get a palindrome (432204424402234).

The spelling of 132002311202003 in words is "one hundred thirty-two trillion, two billion, three hundred eleven million, two hundred two thousand, three".

Divisors: 1 11 12000210109273 132002311202003